Question Correction
The functions are
![f(x) = 3x^2, g(x)=(1)/(3x),$ and h(x) = 3x.](https://img.qammunity.org/2021/formulas/mathematics/college/4kjfcasrv88ziwps6yo5qudol93x2harhe.png)
Answer:
(D)The range of f(x) and h(x) is all real numbers, but the range of g(x) is all real numbers except 0.
(E)The domain of f(x) and h(x) is all real numbers, but the domain of g(x) is all real numbers except 0.
Explanation:
Definition: Given a function f(x):
- The domain of f(x) are the values of x at which f(x) is defined.
- The range of the function are the values of f(x) which is defined.
In g(x), there is no value of x that will make g(x)=0. Therefore, the range of f(x) and h(x) is all real numbers, but the range of g(x) is all real numbers except 0.
In g(x), when x=0
![g(x)=(1)/(3(0))=(1)/(0)](https://img.qammunity.org/2021/formulas/mathematics/college/wn2bpayecljohpc7gt3wsanxkroq04xcsi.png)
Therefore,g(x) is undefined at x=0.
However, at x=0, f(x)=0 and h(x)=0 which are defined.
Therefore, the domain of f(x) and h(x) is all real numbers, but the domain of g(x) is all real numbers except 0.