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Graph the first six terms of a sequence where a1 = 3 and d = −10.

User Luke Miles
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1 Answer

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Answer:

Explanation:

nth term = (n-1)th term + common difference

d = -10

a₁ = 3

a₂ = a₁ + d = 3 + (-10) = -7

a₃ = a₂ + d = -7 + (-10) = -17

a₄ = a₃ + d = -17 + (-10) = -27

a₅ =a₄ + d = -27 + (-10) = -37

a₆ = a₅ + d = -37 + (-10) = -47

First six terms: 3 , -7 , -17, -27, -37 , -47