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What is the approximate value of x? Round to the nearest tenth. A right triangle is shown. Side x is opposite to angle 50 degrees. The hypotenuse has a length of 6 centimeters. Side y is opposite to angle 40 degrees. 3.1 cm 3.9 cm 4.6 cm 5.4 cm

User Wiseman
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2 Answers

7 votes

Answer:

4.6 cm

Explanation:

just took on edge

User Damian Kozlak
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4.8k points
6 votes

Answer:

4.6cm

Explanation:

A diagram showing the analysis from the question has been attached to this response. Kindly download it and view.

From the diagram,

=> We have three angles given

(i) the right angle, 90°

(ii) the angle opposite to side x, 50°

(iii) the angle opposite to side y, 40°

=> We also have one side given,

(i) the hypotenuse, of length 6cm

We can therefore apply the sine rule as follows;


(sin 90^0)/(6) = (sin 50^0)/(x) = (sin 40^0)/(y) ---------------(i)

Now to get the value of x, we'll equation the first and second terms of equation (i) as follows;


(sin 90^0)/(6) = (sin 50^0)/(x) [cross multiply]


xsin90^0 = 6 sin 50^0


x * 1 = 6 * 0.7660


x =4.596 cm = 4.6cm [to the nearest tenth]

Therefore, the value of x is 4.6cm to the nearest tenth

What is the approximate value of x? Round to the nearest tenth. A right triangle is-example-1
User Olambert
by
4.5k points