Question

please help In a video game, a ball moving at 0.6 meter/second collides with a wall. After the collision, the velocity of the ball changed to -0.4 meter/second. The collision takes 0.2 seconds to occur. What’s the acceleration of the ball during the collision? Use . a= v-u/t

Answer 1

the acceleration during the collision is: - 5
`(m)/(s^2)`

Step-by-step explanation:

Using the formula:

`a=(\Delta\,v)/(\Delta\,t)`

we get:

`a=(-0.4-0.6)/(0.2) \,(m)/(s^2) =(-1)/(0.2) \,(m)/(s^2) =-5\,\,(m)/(s^2)`