Question

The nth term of a geometric sequence is given by an = 27(0.1)n - 1. Write the first five terms of this sequence.

Answer 1

The first first five terms of this sequence are

27 ,2.7 ,0.27 ,0.027 , 0.0027

Explanation:

`a(n) = 27(0.1)^(n - 1)`

where n is the number of term

For the first term

n = 1

`a(1) = 27(0.1)^(1 - 1) = 27(0.1) ^(0)`

= 27(1)

= 27

Second term

n = 2

`a(2) = 27(0.1)^(2 - 1) = 27(0.1)^(1)`

= 27(0.1)

= 2.7

Third term

n = 3

`a(3) = 27(0.1)^(3 - 1) = 27(0.1)^(2)`

= 0.27

Fourth term

n = 4

`a(4) = 27(0.1)^(4 - 1) = 27(0.1)^(3)`

= 0.027

Fifth term

n = 5

`a(5) = 27(0.1)^(5 - 1) = 27(0.1)^(4)`

= 0.0027

Hope this helps you