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what is equation of the line passing through the points (2/5, 19/20) and ( 1/3, 11/12 ) in slope intercept form

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Final answer:

The equation of the line passing through the points (2/5, 19/20) and (1/3, 11/12) in slope-intercept form is y = -1/28x + 67/70.

Step-by-step explanation:

To find the equation of the line passing through the points (2/5, 19/20) and (1/3, 11/12) in slope-intercept form, we need to find the slope and the y-intercept.

Step 1:

Find the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

Plugging in the coordinates of the points, we get:

m = (11/12 - 19/20) / (1/3 - 2/5)

m = (-1/60) / (-7/15)

m = - (1/60) * (15/7)

m = -1/28

Step 2:

Use the slope-intercept form: y = mx + b

y = -1/28x + b

Step 3:

Substitute the coordinates of one of the points to find the value of b:

19/20 = -1/28(2/5) + b

Simplifying the equation gives:

19/20 = -1/70 + b

b = 19/20 + 1/70

b = 67/70

Step 4:

Plug the value of b back into the equation:

  • y = -1/28x + 67/70

Therefore, the equation of the line is y = -1/28x + 67/70.

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