Answer:
23.36mL of the stock solution are required.
Step-by-step explanation:
A dilution consist in the addition of solvent to decreases the concentration of a stock solution (The solution more concentrated).
As you want to prepare 250.0mL = 0.2500L of a 0.1342M NaOH, moles of NaOH you require to make this concentration in this volume are:
0.2500L × (0.1342mol / L) = 0.03355 moles of NaOH you require in the diluted solution.
These moles comes from the 1.436M stock solution. The volume of the stock solution you need to add is:
0.03355moles NaOH × (1L / 1.436mol) = 0.02336L of the 1.436M solution =
23.36mL of the stock solution are required.