Answer:
the enthalpy change using Hess's Law in the conversion = -592 KJ
Step-by-step explanation:
If you clearly observe all three reactions mentioned in the question , you will notice that the product of the former reactions becomes the reactant of the later , such that the final product , i.e. pure Si (s) can be obtained by addition of all these three reactions.
SiO₂(s) + 2C(s) ------ Si(impure solid) + 2CO(g) +690
Si(impure solid) + Cl₂(g) ======> SiCl₄(g) -657
SiCl₄(g) + Mg(s) =====> MgCl₂(s) + Si(s) -625
So the enthalpy change for the overall reaction for the formation of pure Si will be given as :
= (+690) + (-657) + (-625)
= -592 KJ