Answer:
25.712 kJ
Step-by-step explanation:
Given that
Initial temperature, T(i) = 300 K
Final temperature, T(f) = 700 K
Heat of the final temperature, Q(f) = 60 kJ
Heat of the initial temperature, Q(i) = ?
Now, we use the relation to solve the question
1 - (T(l)/T(h) = k(max)
1 - (300 / 700) = k(max)
1 - 0.4286 = k(max)
k(max) = 0.5714
Also, k(max) can be used in the relationship
k(max) = W / Q(f)
0.5714 = W / Q(f)
0.5714 * 60 = W
W = 34.284 kJ
Q(l) = 60 - 34.284
Q(l) = 25.716 kJ
Thus, the amount of heat pumped into the 300 K reservoir, is 25.72 kJ