Question

Does anyone mind explaining? I have been stuck on this for a while.

The base of the pyramid is a regular hexagon. Find the volume of the pyramid. Round your answer to the nearest tenth.

Answer 1

vol = 62 in³

Explanation:

First determine r (see attached image) by using pythagorean theorem.

a² = b² + c²

a = 3 in

b = 3/2 = 1.5 in

c = r

3² = 1.5² + r²

r =
`\sqrt{3^(2)-1.5^(2) }`

r = 2.598 in

Get the area = n/2 * a * r

n = number of sides = 6

r = 2.598 in

Area = 6/2 * 3 * 2.598

Area = 23.38 in²

get the volume = 1/3 * Area * h

Area = 23.38 in²

h = 8 in (as given)

vol = 1/3 * 23.38 * 8

vol = 62 in³