Question

What volume, in mL, of a 0.100 M KI solution contains enough KI to react exactly with 15.25 mL of a 0.200 M solution of Cu(NO3)2

Answer 1

Answer: Therefore, the volume of 0.001 M KI is 61 ml.

Step-by-step explanation:

The balanced chemical reaction is :

`2KI+Cu(NO_3)_2\rightarrrow CuI_2+2KNO_3`

According to the neutralization law,

`n_1M_1V_1=n_2M_2V_2`

where,

`M_1` = molarity of
`KI` solution = 0.100 M

`V_1` = volume of
`KI` solution = ?

`M_2` = molarity of
`Cu(NO_3)_2` solution = 0.200 M

`V_2` volume of
`Cu(NO_3)_2` solution = 15.25 ml

`n_1` = valency of
`KI` = 1

`n_2` = valency of
`Cu(NO_3)_2` = 2

Putting in the values we get:

`1* 0.100* V_1=2* 0.200* 15.25`

`V_1=61ml`

Therefore, the volume of 0.001 M KI is 61 ml.