Question

Can you solve this????? Super hard!

Answer 1

`\textbf{J. }(1)/(x^2-x)`

Explanation:

Factor the denominator and cancel the common factor.

`(x+1)/(x^3-x)=(x+1)/(x(x^2-1))=(x+1)/(x(x-1)(x+1))=(1)/(x(x-1))\\\\=\boxed{(1)/(x^2-x)}`