Answer:
![P(14.8< X<16.5)= (16.5-11.1)/(19.2-11.1) -(14.8-11.1)/(19.2-11.1)= 0.667-0.457= 0.210](https://img.qammunity.org/2021/formulas/mathematics/college/64tmqqz2g7qs9yvioxf0l5q1m4s1i4tz32.png)
The probability that it will require between 14.8 and 16.5 minutes to perform the task is 0.210
Explanation:
Let X the random variable "completion times for a job task" , and we know that the distribution for X is given by:
![X \sim Unif (a= 11.1, b= 19.2)](https://img.qammunity.org/2021/formulas/mathematics/college/xtr863h25iujru421tqirkwlq6mtpci6c7.png)
And for this case we wantto find the following probability:
![P(14.8< X<16.5)](https://img.qammunity.org/2021/formulas/mathematics/college/sionmrw7jox4uv6a181f9pnifwi8gpme1x.png)
And for this case we can use the cumulative distribution given by:
![F(x) =(x-a)/(b-a) , a\leq X \leq b](https://img.qammunity.org/2021/formulas/mathematics/college/b75g6v9rjnet0j2zxibi721yt8grgywbmi.png)
And using this formula we got:
![P(14.8< X<16.5)= (16.5-11.1)/(19.2-11.1) -(14.8-11.1)/(19.2-11.1)= 0.667-0.457= 0.210](https://img.qammunity.org/2021/formulas/mathematics/college/64tmqqz2g7qs9yvioxf0l5q1m4s1i4tz32.png)
The probability that it will require between 14.8 and 16.5 minutes to perform the task is 0.210