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A production manager at a wall clock company wants to test their new wall clocks. The designer claims they have a mean life of 1515 years with a variance of 2525. If the claim is true, in a sample of 4141 wall clocks, what is the probability that the mean clock life would differ from the population mean by more than 0.40.4 years

User Rob Wilson
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1 Answer

1 vote

Answer:

The correct answer will be "0.3043".

Explanation:

The given values are:


\mu = 15


n=41


\sigma^2=25

then,


\sigma=5

If researchers know representative sample n > 30 and default deviation those who use z-test


P(x>15.4)


1-P(x<15.4)


1-P((x-\mu)/((\sigma)/(√(n) ) ) <(15.4-15)/((5)/(√(41) ) ) )


1-P(Z<0.51225)


1-0.695762


0.3043

User Oscar Nieto
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