Question

What is the boiling point of a solution that contains 3 moles of KBr in 2000 g of water?

A. 97°C

B. 103°C

C. 101.5°C

D. 99.7°C

Answer 1

C. 101.5°C

Step-by-step explanation:

The computation of the boiling point of a solution is shown below:

As we know that

`\Delta T = i K_bm`

where,

i = Factor of Van’t Hoff i.e 2KBr

K_b = Boiling point i.e 0.512° C

m = molality
`= (Moles\ of\ solute)/(Solvent\ mass)`

Now place the values to the above formula

So, the boiling point is

`(T - 100^\circ C) = 2* 0.512^\circ * (3.00\ ml)/(2.00\ kg)`

After solving this, the t is

= 100° C + 1.536° C

= 101.536° C

Hence, the correct option is C.