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Find the equation of circle (5,1) diameter 4 square root 5​

User SquareCog
by
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1 Answer

9 votes

Answer:


(x-5)^2+(y-1)^2=20

Explanation:

Equation of a circle


(x-a)^2+(y-b)^2=r^2

(where (a, b) is the center and r is the radius)

Given:

  • center = (5, 1)
  • diameter = 4√5

Diameter = 2r (where r is the radius)

⇒ r = 4√5 ÷ 2 = 2√5

Substituting these values into the equation:


\implies (x-5)^2+(y-1)^2=(2√(5))^2


\implies (x-5)^2+(y-1)^2=20

User Bta
by
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