Find the equation of circle (5,1) diameter 4 square root 5

Question

asked Mar 2, 2023 37.7k views

1 Answer

Bta · Answer 1 · 2023-03-07T17:41:58+0000

Answer:

(x-5)^2+(y-1)^2=20

Explanation:

Equation of a circle

(x-a)^2+(y-b)^2=r^2

(where (a, b) is the center and r is the radius)

Given:

Diameter = 2r (where r is the radius)

⇒ r = 4√5 ÷ 2 = 2√5

Substituting these values into the equation:

$\implies (x-5)^2+(y-1)^2=(2√(5))^2$

$\implies (x-5)^2+(y-1)^2=20$