Question

Find the velocity. Please help!

Answer 1

48.03 m/s

Step-by-step explanation:

acceleraion, a = 3.7 m/s^2

distance traversed, S = 300-25 = 275 m

initial velocity, v0 = 16.5 m/s

Using kinematics formula

v1^2 - v0^2 = 2aS

Final velocity,

v1 = sqrt(2aS + v0^2)

= sqrt(2*3.7*275 + 16.5^2)

= 48.03 m/s

Answer 2

48 m/s

Step-by-step explanation:

Given:

Δx = 300 m − 25 m = 275 m

v₀ = 16.5 m/s

a = 3.7 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (16.5 m/s)² + 2 (3.7 m/s²) (275 m)

v = 48 m/s