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What is the value of the equilibrium constant Kcif the concentration of NO and NOBr are 0.10 M and

the concentration of Br2 is 3.0 M?
2NOBr(8) = 2NO(g) + Br2(g)

2 Answers

1 vote

Answer:

3

Step-by-step explanation:

User Keith G
by
5.3k points
5 votes

Answer:

3

Step-by-step explanation:

Data obtained from the question include:

Concentration of NO, [NO] = 0.1M

Concentration of NOBr, [NOBr] = 0.1M

Concentration of Br, [Br2] = 3M

Equilibrium constant, Kc =..?

The equilibrium constant, Kc is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Thus, the equilibrium constant, Kc for reaction can be obtained as follow:

2NOBr <==> 2NO + Br2

Kc = [NO]² [Br2] /[NOBr]²

[NO] = 0.1M

[NOBr] = 0.1M

[Br2] = 3M

Kc =..?

Kc = [0.1]² [3] /0.1]²

Kc = 3

Therefore, the equilibrium constant Kc, for the reaction is 3.

User Mirko Stocker
by
4.6k points