Question

A force of 6 N is used to open a door, wherein the distance of the force to the axis of rotation is 80 cm. If the angular acceleration it acquires is 0.5 rad/s 2, determine the moment of inertia of the door.

Answer 1

Step-by-step explanation:

∑τ = Iα

(6 N) (0.80 m) = I (0.5 rad/s²)

I = 9.6 kg m²