Answer:
6.67 rad/s²
Step-by-step explanation:
Assuming the pulley is a solid disk or cylinder, the moment of inertia is I = ½ mr².
∑τ = Iα
(8 N) (0.60 m) = ½ (4 kg) (0.60 m)² α
α = 6.67 rad/s²
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