Question

g At 4 ft. from a point source of gamma radiation the intensity is 158 mRem/hr. How far away would you have to move to decrease the intensity to 17 mRem/hr.? [I1/I2 = (D2)2/(D1)2] I1(D1)2 = I2(D2)2

Answer 1

You will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.

Step-by-step explanation:

The distance can be calculated using the following equation:

`(I_(1))/(I_(2)) = (D_(2)^(2))/(D_(1)^(2))`

Where:

I₁ = 158 mRem/h

I₂ = 17 mRem/h

D₁ = 4 ft.

D₂=?

Hence, the distance D₂ is:

`D_(2) =\sqrt{(I_(1))/(I_(2))*D_(1)^(2)} = \sqrt{(158 mRem/h)/(17 mRem/h)*(4 ft)^(2)} = 12.2 ft`

Therefore, you will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.

I hope it helps you!