Question

The sum of three consecutive integers is four more than twice the third. Find
the integers.

Answer 1

Integers are 5,6,7

Explanation:

Let Three consecutive integers be x,x+1,x+2

sum=x+(x+1)+(x+2)=x+x+x+1+2=3x+3

twice of third number=(x+2)*2=2x+4

Four more than twice of third integer = 4+2x+4

therefore

sum= 4+ twice of third integer

3x+3= 4+2x+4

3x-2x=8-3

x=5

therefore the numbers are=x=5

x+1=6

x+2=7

Answer 2

They are 5,6 and 7.

Explanation:

Let the integers be x, x+1, x+2.

x + x + 1 + x + 2 = 2(x + 2) + 4

3x + 3 = 2x + 8

x = 8 - 3 = 5.