Question

I’m confused can ya help me

Answer 1

C & D

Explanation:

x² + 3x - 3 = 0

a = co efficient of x² = 1

b= co efficient of x = 3

c = constant = -3

roots = (-b ±
`√(b-4ac)`)/2a

= (-3±
`\sqrt{3^(2)-4*1*[-3]}` )/2*1

= (-3±
`√(9+12)`)/2

= (-3±√21)/2

`x = (-3+√(21))/(2) ; x =(-3-√(21))/(2)`