Question

A coil with a self-inductance of 6.0 H is connected to a dc source through a switch. As soon as the switch is closed at t = 0 s, the rate of change of current is 2.0 A/s. What is the emf induced in this coil at t = 0 s?

Answer 1

The emf induced in this coil at the given time is 12 V

Step-by-step explanation:

Given;

a coil with a self-inductance, L = 6.0 H

rate of change of current in the coil, di/dt = 2.0 A/s

The emf induced in this coil at t = 0 s, is calculated as;

`emf = L (di)/(dt)`

where;

L is the inductance (H)

`(di)/(dt)` is the rate of change of time (A/s)

Substitute in the given values and solve for the emf

`emf = L(di)/(dt) \\\\emf = 6*2\\\\emf = 12 \ V`

Therefore, the emf induced in this coil at the given time is 12 V