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A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 4.40 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much
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A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 4.40 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do

User James Waddington
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1 Answer

2 votes

Answer:

F = umg where u is coefficient of dynamic friction

Step-by-step explanation:

F = 0.4 x 80 x 9.81 = 313.92 N

User Mads Ohm Larsen
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