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1 vote
How to solve the equation 4×3−15÷3×2+1

User Ying
by
6.0k points

2 Answers

6 votes

Answer: 3

Explanation:

PEMDAS

P: No parenthesis

E: No exponents

M and D: 4x3 = 12(12-15÷3×2+1), 15÷3 = 5(12-5×2+1), 5*2 = 10(12-10+1)

A and S: 12-10 = 2(2+1), 2+1=3(3)

User Mdanishs
by
6.7k points
5 votes

Answer:

3

Explanation:

We use Order of Operations BPEMDAS.

Step 1: Multiply

12 - 15/3(2) + 1

Step 2: Divide

12 - 5(2) + 1

Step 3: Multiply

12 - 10 + 1

Step 4: Subtract

2 + 1

Step 5: Add

3

User Ede
by
5.0k points