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Insert four irrational numbers between 3 root 2 and 2 root 3

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Answer:

3√2 > √17 > √15 > √14 > √13 > 2√3

Explanation:


3\sqrt2=√(3^2\cdot2)=√(18)\\\\2\sqrt3=√(2^2\cdot3)=√(12)\\\\18>17>15>14>13>12\ \implies\ 3\sqrt2>√(17)>√(15)>√(14)>√(13)>2√(3)

{√16 = 4 is rational}

User Jahra
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