Question

Please help me out with these questions. It's trigonometry

Answer 1

Explanation:

LOOK AT THE PICTURE

In ΔABC:

`\sin\alpha=(x)/(y+p)\\\\\cos\alpha=(q)/(y+p)\\\\\tan\alpha=(x)/(q)`

In ΔADC

`\sin\alpha=(y)/(x)\\\\\cos\alpha=(z)/(x)\\\\\tan\alpha=(y)/(z)`

In ΔBCD

`\sin\alpha=(z)/(q)\\\\\cos\alpha=(p)/(q)\\\\\tan\alpha=(z)/(p)`