Answer:
![P(X < 3) = 67.14\%](https://img.qammunity.org/2021/formulas/business/college/2c0vvn3s5iic9n119sknew9xo9m658x601.png)
Therefore, 67.14% of the cars can get through the toll booth in less than 3 minutes.
Step-by-step explanation:
A consultant working for the state concluded that if service times are measured from the time a car stops in line until it leaves, service times are exponentially distributed with a mean of 2.7 minutes.
Let X be a random variable. The service time has an exponential distribution with a mean of 2.7 minutes.
Mean = μ = 2.7 minutes
Decay rate = m = 1 /μ
Decay rate = m = 1/2.7
Decay rate = m = 0.371
The cumulative probability distribution function is given by
![P(X < x) = 1 - e^(-mx)](https://img.qammunity.org/2021/formulas/business/college/o4txksupsgconf5orlsxrosca0xl5e3u8b.png)
Where m is the decay rate and x < 3
So the proportion of cars that can get through the toll booth in less than 3 minutes is
![P(X < 3) = 1 - e^(-0.371(3))](https://img.qammunity.org/2021/formulas/business/college/nu0b7e6z5w3ct1ilpz8e53ryq4ops2wd07.png)
![P(X < 3) = 1 - 0.3286](https://img.qammunity.org/2021/formulas/business/college/xwmcjw047e03ym1ptmjzq816mhkffwz2tn.png)
![P(X < 3) = 0.6714](https://img.qammunity.org/2021/formulas/business/college/ueyjetlc7lsm127m1nz94xtb582jmqbetd.png)
![P(X < 3) = 67.14\%](https://img.qammunity.org/2021/formulas/business/college/2c0vvn3s5iic9n119sknew9xo9m658x601.png)
Therefore, 67.14% of the cars can get through the toll booth in less than 3 minutes.