Question

a fly undergoes a displacement of - 5.80 while accelerating at -1.33 m/s^2 for 4.22 s. what was the initial velocity of the fly?

Answer 1

`v_i = 1.44(m)/(s)`

Step-by-step explanation:

The computation of the initial velocity of the fly is shown below:-

But before that we need to do the following calculations

For 4.22 seconds

`\bar v = (-5.80 m)/(4.22 s)`

`= -1.37(m)/(s)`

For uniform acceleration

`\bar v = (v_i +v_f)/(2)`

`= v_i + v_f`

`= -2.74(m)/(s)`

With initial and final velocities

`= -1.33(m)/(s^2)`

`= (v_i +v_f)/(4.22s)`

`= -v_i + v_f`

`= -5.61(m)/(s)`

So, the initial velocity is

`v_i = 1.44(m)/(s)`

We simply applied the above steps to reach at the final solution i.e initial velocity