Answer:
B
Explanation:
A rational expression is undefined when the denominator of the expression equals 0 (this is because anything over 0 is undefined). In other words, to find the values for which the given expression is undefined, we simply have to find the zeros of the denominator. We can ignore the numerator. Thus, let:
![0=x^2+2x-63](https://img.qammunity.org/2021/formulas/mathematics/high-school/kan2rfhb6nkn9qckq0o45e9mm6tg4baiu6.png)
This is now a quadratic. Solve for the quadratic. I will factor but you can do whatever you like (complete the square, quadratic formula, etc.).
We notice that two factors that multiply to -63 and also add to +2 is 9 and -7. Thus:
![0=(x+9)(x-7)](https://img.qammunity.org/2021/formulas/mathematics/high-school/7gimf42wroyt8u8dupyv9urep5lwy0iqf6.png)
![x+9=0 ; x=-9](https://img.qammunity.org/2021/formulas/mathematics/high-school/cy0rlahezgestvo2bhrjn1y8bnwwl8ht5f.png)
![x-7=0; x=7](https://img.qammunity.org/2021/formulas/mathematics/high-school/bzeigh2csqidf6qy54hu7jkup9g37bn3ec.png)
The zeros are -9 and 7.
The denominator will equal 0 at these values, and the expression will be undefined.