Question

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Answer 1

b.)

`(7)/(8) - (1)/(4) * (1)/(2)`

Solve the ones multiplying first

That's

`- ( 1)/(4) * (1)/(2) = (1)/(8)`

Subtract

`(7)/(8) - (1)/(8) = (6)/(8) = (3)/(4)`

c.)

`(5)/(6) + (2)/(3) / (1)/(4)`

Division first

`(2)/(3) / (1)/(4) = (2)/(3) * 4 = (8)/(3)`

Add

Final answer is

`(5)/(6) + (8)/(3) = (5 + 10)/(6) = (15)/(6)`

d.)

`(5)/(16) - (11)/(10) / (22)/(5)`

Division first

That's

`(11)/(10) / (22)/(5) = (11)/(10) * (5)/(22) = (1)/(4)`

Subtract

We have the final answer as

`(5)/(16) - (1)/(4) = (5 - 4)/(16) = (1)/(16)`

g).

`( (3)/(4) + (2)/(3) ) * (1)/(2)`

Solve the terms in the bracket first

That's

`(3)/(4) + (2)/(3) = (9 + 8)/(12) = (17)/(12)`

Multiply

We have the final answer as

`(17)/(12) * (1)/(2) = (17)/(24)`

j ).

`( (10)/(7) - (1)/(2) ) * ( (2)/(3) + (5)/(6) )`

Solve all the terms in the bracket first

That's

`(10)/(7) - (1)/(2) = (20 - 7)/(14) = (13)/(14)`

And

`(2)/(3) + (5)/(6) = (4 + 5)/(6) = (9)/(6) = (3)/(2)`

Multiply

We have the final answer as

`(13)/(14) * (3)/(2) = (39)/(28)`

Hope this helps you.