Question

PLSS HELP. ALGEBRA 1. 9TH GRADE..ASAP PLSSS

Answer 1

y = - 4

Explanation:

`\cfrac{2}{5}\left(10y-5\right)-2y=-10` (Multiply)

`\cfrac{2\left(10y-5\right)}{5}-2y=-10`

`\cfrac{2\left(10y-5\right)}{5}* \:5-2y* \:5=-10* \:5`

`2\left(10y-5\right)-10y=-50` (Expand)

`10y-10=-50`

`10y-10+10=-50+10` ( Add 10)

`10y=-40` (Simplify)

`\cfrac{10y}{10}=\cfrac{-40}{10}` (Divide by 10)

`y=-4`

Answer 2

`y=-4`

Explanation:

Given equation:

`(2)/(5)(10y-5)-2y=-10`

Expand the brackets:

`\implies (2)/(5)(10y)-(2)/(5)(5)-2y=-10`

`\implies (2 \cdot 10)/(5)y-(2 \cdot 5)/(5)-2y=-10`

`\implies (20)/(5)y-(10)/(5)-2y=-10`

`\implies 4y-2-2y=-10`

Collect like terms:

`\implies 4y-2y-2=-10`

Combine like terms:

`\implies 2y-2=-10`

Add 2 to both sides:

`\implies 2y-2+2=-10+2`

`\implies 2y=-8`

Divide both sides by 2:

`\implies (2y)/(2)=(-8)/(2)`

`\implies y=-4`