Question

At the movie theatre, child admission is $5.10 and adult admission is $9.00 .

On Wensday, twice as many adults tickets as child tickets were for a total of $831.60.

How many child tickets were sold that day?

Answer 1

`5.10 X +9.00 Y = 831.60`

We also know that for Wedneday we have two times tickets for adults compared to child so we have

`Y =2x`

And using this condition we have:

`5.10 X + 18 X = 831.60`

And solving for X we got:

`X= (831.60)/(23.1)=36`

So then the number of tickets sold for child are 36

Explanation:

For this problem we can set upt the following notation

X = number of tickets for child

Y= number of tickets for adults

And we know that the total revenue for Wednesday was 831.60. So then we can set up the following equation for the total revenue

`5.10 X +9.00 Y = 831.60`

We also know that for Wedneday we have two times tickets for adults compared to child so we have

`Y =2x`

And using this condition we have:

`5.10 X + 18 X = 831.60`

And solving for X we got:

`X= (831.60)/(23.1)=36`

So then the number of tickets sold for child are 36