Question

n electromagnetic wave in vacuum has an electric field amplitude of 611 V/m. Calculate the amplitude of the corresponding magnetic field.

Answer 1

The corresponding magnetic field is

Step-by-step explanation:

From the question we are told that

The electric field amplitude is
`E_o = 611\ V/m`

Generally the magnetic field amplitude is mathematically represented as

`B_o = (E_o )/(c )`

Where c is the speed of light with a constant value

`c = 3.0 *0^(8) \ m/s`

So

`B_o = (611 )/(3.0*10^(8))`

`B_o = 2.0 4 *10^(-6) \ Vm^(-2) s`

Since 1 T is equivalent to
`V m^(-2) \cdot s`

`B_o = 2.0 4 *10^(-6) \ T`