Question

`\sf Solve \;it \; with \; steps:-`


`\bf 3\left(2x+2\right)=\:4x-10`

~ frεε

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}`

`\textbf{Let's solve :}`

`\qquad \sf  \dashrightarrow \:3(2x + 2) = 4x - 10`

`\qquad \sf  \dashrightarrow \:6x + 6 = 4x - 10`

`\qquad \sf  \dashrightarrow \:6x - 4x = - 10 - 6`

`\qquad \sf  \dashrightarrow \:2x = - 16`

`\qquad \sf  \dashrightarrow \:x = - 16 / 2`

`\qquad \sf  \dashrightarrow \:x = - 8`

`\textsf{Hence, value of x is -8}`

Answer 2

`\boxed{\sf \bold{x = -8}}`

Step-by-step explanation:

3(2x+2)= 4x -10

apply distributive method: a(b+c) = ab + ac

3(2x) + 3(2) = 4x - 10

multiply

6x + 6 = 4x - 10

subtract both sides by 4x

6x + 6 - 4x = 4x - 10 -4x

simplify

2x + 6 = -10

subtract both sides by 6

2x + 6 -6 = -10 -6

simplify

2x = -16

divide both sides by 2

x = -8