Answer:
When the temperature of the gas is increased from 20 to 40, the pressure will be 2p
Step-by-step explanation:
Given;
initial temperature of the gas, T₁ = 20 K
final temperature of the gas, T₂ = 40 k
initial pressure of the gas, P₁ = P
final pressure of the gas, P₂ = ?
Apply pressure law of gases;
![(P_1)/(T_1) = (P_2)/(T_2) \\\\P_2 = (P_1T_2)/(T_1) \\\\P_2 = (40P)/(20) \\\\P_2 = 2P](https://img.qammunity.org/2021/formulas/physics/college/3o37n5dwrbwufd19txi7n1dgvt7lnqjsqr.png)
Therefore, when the temperature of the gas is increased from 20 to 40, the pressure will be 2p