Question

For a given sample of C3H8(g), the enthalpy change during the reaction is -784kJ. How many grams of CO2 are produced? Group of answer choices g

Answer 1

`m_(CO_2)=46.6gCO_2`

Step-by-step explanation:

Hello,

In this case, considering the combustion of propane:

`C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)\ \ \ \Delta _CH=-2220.0 kJ/mol`

We can compute the burnt moles of propane as shown below:

`n=(-784kJ)/(-2220.0 kJ/mol) =0.353molC_3H_8`

Then, by noticing propane and carbon dioxide are in a 1:3 molar ratio, we can compute the grams carbon dioxide by using the shown below stoichiometric procedure:

`m_(CO_2)=0.353molC_3H_8*(3molCO_2)/(1molC_3H_8) *(44gCO_2)/(1molCO_2) \\\\m_(CO_2)=46.6gCO_2`

Best regards.