Question

In the Haber process, nitrogen gas is combined with hydrogen (from natural gas) to form ammonia. If ammonia is formed at 0.345 M/s, how quickly is the nitrogen gas disappearing

Answer 1

`r_(N_2)=-0.1725M/s`

Step-by-step explanation:

Hello,

In this case, by means of the law of mass action, we firstly write the described chemical reaction:

`N_2(g)+3H_2(g)\rightarrow 2NH_3(g)`

Thus, as ammonia is being formed at 0.345 M/s, nitrogen will be disappearing at (consider law of mass action):

`r_(NH_3)=0.345M/s\\\\(1)/(-1) r_(N_2)=(1)/(-3)r_(H_2)=(1)/(2) r_(NH_3)\\\\r_(N_2)=-(1)/(2) r_(NH_3)=-(1)/(2) *0.345M/s\\\\r_(N_2)=-0.1725M/s`

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