Answer:
d. A weak base
Step-by-step explanation:
For this question, we have to start with the reaction between
and
. So:
![HF~+~NaOH~->~NaF~+~H_2O](https://img.qammunity.org/2021/formulas/chemistry/college/9bkfd5z0xm0ti6mxi3p9fpe2s2nkmcwpeo.png)
Now, we have to analyze each compound:
Fluorhydric acid HF this is a strong acid because it has the ability to produce hydronium ions
![H^+](https://img.qammunity.org/2021/formulas/chemistry/high-school/krcod3ifzadtnv06i2rij3erde1xulcg1z.png)
Sodium hydroxide NaOH this is a strong base because it has the ability to produce hydroxide ions
![OH^-](https://img.qammunity.org/2021/formulas/chemistry/high-school/xft2lnnboil9bmx68ui0g7mqnspvfu0mt2.png)
Sodium fluoride NaF is a salt in which the cation is
and the anion is
![F^-](https://img.qammunity.org/2021/formulas/chemistry/high-school/x7lb2vv87ymk5wtoar2llxya7y6oodqsy6.png)
Water Is a neutral molecule usually the solvent
Now, we have the reaction of a strong acid with a strong base. If we remember the conjugated base theory, a strong acid will produce a weak base. So, NaF is a weak base. We also have water, but this is a neutral molecule. With this in mind, the answer is d.
I hope it helps!