Question

g A canyon is 1200 meters deep at its deepest point. A rock is dropped from the rim above this point. How long will it take the rock to hit the canyon floor

Answer 1

t = 15.6 s

Explanation:

According to the kinematic equation:

`y_(f) = y_(0) + v_(0)*t - (1)/(2)gt^(2)` (1)

Where:

`y_(f)`: is the final position = 1200 m

y₀: is the initial position = 0 m

V₀: is the initial speed = 0 m/s

g: is the gravity = 9.81 m/s²

t: is the time =?

From equation (1) we have:

`-1200 m = 0 + 0*t - (1)/(2)*9.81 m/s^(2)*t^(2)`

`t^(2) = \frac{2*(1200 m)}{9.81 m/s{2}}`

`t = 15.6 s`

Therefore, it will take 15.6 seconds to the rock to hit the canyon floor.

I hope it helps you!