Question

Find the equation of the line with slope m= 1/5
that contains the point (-10, 5).

Answer 1

y=1/5x+7

1/5 is the slope and in an equation it is m. So in an equation it will be y=1/5x+b. b is the y intercept so we can substitute the coordinates for x and y. 5=1/5*-10 + b. Now we solve for b. 5= -2+b. Next it will be 5+2=b. 7=b. Now we can substitute the variables in the equation.
Therefore, the equation is y=1/5x+7

Answer 2

y = 1/5x +7

Explanation:

The equation of a line is given by

y = mx+b where m is the slope and b is the y intercept

y =1/5 x + b

Substitute the point into the equation

5 = 1/5 (-10) +b

5 = -2 +b

Add 2 to each side

7 = b

y = 1/5x +7