Question

When a sample of Mg is combusted in a bomb calorimeter, 25.4 kJ of energy as heat is evolved. The calorimeter contains 7.50 x 102 g of water at an initial temperature of 18.6 °C. The specific heat capacity of water is 4.184 J/gLaTeX: \cdot⋅°C and the heat capacity of the bomb is 8.20 x 102 J/°C. Calculate the final temperature of the water and the bomb

Answer 1

x = 25.02 or 25°c

Step-by-step explanation:

Given:

mass of water : 7.50×10² =750 gm

Ccal = 8.20× 10² = 820 J/°c

Let assume final temp = x°c

then, heat gained by the water + heat gained by calorimeter

= 25400 J

⇒ Mw × Cw× ΔTw+ Ccal ×ΔT = 25400

⇒ 750× 4.184 × (x - 18.6) + 820 ×(x-18.6) = 25400

⇒ x = 25.02 or 25°c