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It is given that and are right angles, and . Since they contain right angles, ΔABR and ΔACR are right triangles. The right triangles share hypotenuse , and reflexive property justifies that . Since and , the transitive property justifies . Now, the hypotenuse and leg of right ΔABR is congruent to the hypotenuse and the leg of right ΔACR, so by the HL congruence postulate. Therefore, ________ by CPCTC, and bisects by the definition of bisector.

User Deadtime
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2 Answers

4 votes

Answer:

A) <BAR = <CAR

Explanation:

Edge

User Abel Olguin Chavez
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THIS IS THE COMPLETE QUESTION BELOW;

Complete the paragraph proof. Given: ∠ABR and ∠ACR are right angles AB ≅ BC BC ≅ AC Prove: bisects ∠BAC

It is given that ∠ABR and ∠ACR are right angles, AB ≅ BC and BC ≅ AC Since they contain right angles, △ABR and △ACR are right triangles. The right triangles share hypotenuse AR, and reflexive property justifies that AR ≅ AR. Since AB ≅ BC and BC ≅ AC, the transitive property justifies AB ≅ AC. Now, the hypotenuse and leg of right △ABR is congruent to the hypotenuse and the leg of right △ACR, so △ABR ≅ △ACR by the HL congruence postulate. Therefore, by CPCTC, and bisects ∠BAC by the definition of bisector.

Answer:

The answer is ∠BAR=∠CAR

Explanation:

From the question, In the ΔABR and ΔACR , AB=AC=X

CHECK THE ATTACHMENT FOR DETAILED STEP BY STEP EXPLANATION:

It is given that and are right angles, and . Since they contain right angles, ΔABR-example-1
User Deanne
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