Question

Find the inductive reactance per mile of a single-phase overhead transmission line operating at 60 Hz, given the conductors to be Patridge and the spacing between centers to be 20 ft

Answer 1

The inductive reactance is 0.8281 Ω/mile

Step-by-step explanation:

Given;

frequency, f = 60 Hz

space between the center, GMD = 20 ft

The inductive reactance per mile is calculated as;

`X_L =X_a + X_d\\\\X_L = 2.022*10^(-3) *f *ln(1)/(GMR) + 2.022*10^(-3) *f *ln\ GMD`

Where;

GMR is geometric mean radius (obtained from manufacturer's table)

GMD is geometric mean distance

For Partridge conductor, GMR = 0.0217 ft;

Xa = 2.022 x 10⁻³ x 60 x ln (1 / 0.0217)

Xa = 0.4647 Ω/mile

`X_d` = 2.022 x 10⁻³ x f x ln GMD

`X_d` = 2.022 x 10⁻³ x 60 x ln(20)

`X_d` = 0.3634 Ω/mile

Inductive reactance;

`X_L = X_a + X_d\\\\X_L = 0.4647 \ ohms/mile \ + 0.3634 \ ohms/mile\\\\X_L = 0.8281 \ ohms/mile`

Therefore, the inductive reactance is 0.8281 Ω/mile