Answer:
The correct answer is First option:
![22x+10y=7\\ 2x-y=-2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tumjjvhjgrandj16058jtmix6dh5ubp8io.png)
Explanation:
We are given 4 equations:
![22x+10y=7\\ 2x-y=-2\\3x+2y=5\ and\ \\4x-y=2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yr43hts2dthe73n0yjlt5g1bgyrtgsvhbu.png)
Let us solve the first two:
![22x+10y=7...... (1)\\ 2x-y=-2 ...... (2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8r8vzm0pu9uxdn3vrv20lzxmuwovsvqex7.png)
Multiplying (2) with 10 and adding to (1):
![22x+20x=7-20\\\Rightarrow 42x=-12\\\Rightarrow x = -0.2857 \approx -0.3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bbo713xnvc9t19npou9l4nlpqrlsjobgh3.png)
So, approximately, value of x is -0.3.
Putting value of x in (2):
![2 * -0.3 - y =-2\\\Rightarrow y = -0.6+2\\\Rightarrow y = 1.4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/i5jqusmsjjjys0i5a73qaulmzchlrrjh1l.png)
value of x is approximately -0.3 so y is approximately 1.4.
So, the solution is
(–0.3, 1.4)
The correct answer is First option:
![22x+10y=7\\ 2x-y=-2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tumjjvhjgrandj16058jtmix6dh5ubp8io.png)
The above two equations have a solution approximately (–0.3, 1.4).