Question

What value of D is required to make vt = 42.7 m/s the terminal velocity of a skydiver of mass 85.0 kg . Express your answer using two significant figures.

Answer 1

Complete Question

For a human body falling through air in a spread edge position , the numerical value of the constant D is about
`D = 0.2500 kg/m`

What value of D is required to make vt = 42.7 m/s the terminal velocity of a skydiver of mass 85.0 kg . Express your answer using two significant figures?

Answer:

The value of D is
`D = 0.457 \ kg/m`

Step-by-step explanation:

From the question we are told that

The terminal velocity is
`v_t = 42.7 \ m/s`

The mass of the skydiver is
`m = 85.0 \ kg`

The numerical value of D is
`D = 0.2500 kg/m`

From the unit of D in the question we can evaluate D as

`D = (m * g )/(v^2)`

substituting values

`D = (85 * 9.8 )/((42.7)^2)`

`D = 0.457 \ kg/m`