Question

a private opinion poll is conA private opinion poll is conducted for a politician to determine what proportion of the population favors decriminalizing marijuana possession. How large a sample is needed to be 92% confident that the sample proportion will not differ from the true proportion by more than 2% ducted for a politician to determine

Answer 1

Answer: 1,914

Explanation:

first we take down the information given to us

For 92% confidence, z = 1.75

Error of margin E = 2% = 0.02

Since no estimate of population proportion has been given, we will assume:

p = q = 0.50

Hence,

Sample size required n

n = ( z/E)² × p × q

n = ( 1.75/0.02)² × 0.5 × 0.5

n = (87.5)² × 0.5 ×0.5

n = 1914