Question

A sample of a pure compound that weighs 60.3 g contains 20.7 g Sb (antimony) and 39.6 g F (fluorine). What is the percent composition of fluorine

Answer 1

The percent composition of fluorine is 65.67%

Step-by-step explanation:

Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.

That is, the percentage composition is the percentage by mass of each of the elements present in a compound.

The calculation of the percentage composition of an element is made by:

In this case, the percent composition of fluorine is:

percent composition of fluorine= 65.67%

The percent composition of fluorine is 65.67%

Answer 2

The percent composition of fluorine is 65.67%

Step-by-step explanation:

Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.

That is, the percentage composition is the percentage by mass of each of the elements present in a compound.

The calculation of the percentage composition of an element is made by:

`percent composition element A=(total mass of element A)/(mass of compound) *100`

In this case, the percent composition of fluorine is:

`percent composition of fluorine=(39.6 g)/(60.3 g) *100`

percent composition of fluorine= 65.67%

The percent composition of fluorine is 65.67%