Answer:

With the confidence level we can find the significance level:

And the value for
. Then we can use the normal standard distribution and we can find a quantile who accumulates 0.1 of the area on each tail and we got:

Explanation:
For this problem we have the confidence level given

With the confidence level we can find the significance level:

And the value for
. Then we can use the normal standard distribution and we can find a quantile who accumulates 0.1 of the area on each tail and we got:
